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("cosh x + 1")/("cosh x -1") = "coth "^2...

`("cosh x + 1")/("cosh x -1") = "coth "^2x/k, "then k"=`

A

`1`

B

`-1`

C

`2`

D

`3`

Text Solution

Verified by Experts

The correct Answer is:
C
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