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log(4)2-log(8)2+log(16)2-....=...

`log_(4)2-log_(8)2+log_(16)2-....=`

A

`e^(2)`

B

`log_(2)`

C

`+log_(e)3`

D

`1-log_(e)2`

Text Solution

Verified by Experts

The correct Answer is:
D
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