What will be the length of mercury column in a barometer tube, when the atmospheric pressure is 76 cm of mercury and the tube is inclined at an angle of `30 ^(@)` with the horizontal direction ?
Text Solution
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Here, h=76 cm `theta=30^(@)` If l is the length of mercury column is the barometer tube then `(h)/(l)=sin 30^(@) implies (76cm)/(l)=(1)/(2)` `implies " " l=2xx76=152 cm`
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