In the reaction `._1^2 H + ._1^3 H rarr ._2^4 He + ._0^1 n`, if the binding energies of `._1^2 H, ._1^3 H` and `._2^4 He` are respectively `a,b` and `c` (in MeV), then the energy (in MeV) released in this reaction is.

Options

A. c+a+b
B. c-a-b
C. a+b+c
D. a+b-c

Answer

B

Explanation

During fusion, BE of daughter nucleus is always sreater than the total energy of the parent muclei, so energy released
= c - (a + b) = c -a b