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Two redioactive materials X(1)andX(2) ha...

Two redioactive materials `X_(1)andX_(2)` have decay constants `10lamdaandlamda`, respecitvely. If initially they have the same number of nuclei, then the ratio of the number of nuclei of `X_(1)` to that of `X_(2)` will be 1/e after a time

A

`(1)/((10lamda))`

B

`((1)/(11lamda))`

C

`(11)/((10lamda))`

D

`(1)/((9lamda))`

Text Solution

Verified by Experts

The correct Answer is:
D
We have, `1/e=(N_(0)e^(-10lamdat))/(N_(0)e^(-lamdat))=e^(9lamdat)ort=(1)/(9lamda)(given(N_(1))/(N_(2))=1/e)`
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