What is the binding energy per nucleon of `_(6)C^(12)`nucleus?
Given , mass of `C^(12)` `(m_(c))_(m)` = 12.000 u
Mass of proton `m_(p)` = 1.0078 u
Mass of neutron `m_(n)` = 1.0087 u
and 1 amu = 931.4 MeV

Options

A. 5.26 MeV
B. 6.2 MeV
C. 4.65 MeV
D. 7.68 MeV

Answer

D

Explanation

Binding energy per nucleon
`([{m_(p)Z+m_(n)(A-Z)}-M]xx931)/("Mass number A")`
`=((6xx1.0078+6xx1.0087-12)/(12))xx931.4`
= 7.68 MeV