The energy released by the fission of a single uranium nucleus is `200 MeV`. The number of fission of uranium nucleus per second required to produce `16 MW` of power is (Assume efficiency of the reactor is `50%`)

Options

A. `0.5xx10^(14)`
B. `0.5xx10^(22)`
C. `5xx10^(12)`
D. `5xx10^(14)`

Answer

D

Explanation

Energy released in the fission of one nucleus = 200 MeV
`=200xx10^(6)xx1.6xx10^(19)=3.2xx10^(11)J`
`P=16kW =16xx10^(3)` Watt
Now, number of nuclei required per second
`n=P/E=(16xx10^(3))/(3.2xx10^(11))=5xx10^(14)`