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A radioactive nucleus is being produced ...

A radioactive nucleus is being produced at a constant rate `alpha` per second. Its decay constant is `lamda`. If `N_0` are the number of nuclei at time `t = 0`, then maximum number of nuclei possible are.

A

`(alpha)/(lamda)`

B

`N_(0)+(alpha)/(lamda)`

C

`N_(0)`

D

`(alpha)/(lamda)+N_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A
Maximum number of unclei will be present when rate of decay= rate of formation
`lamdaN=alpha`
Maximum number of nuclei, `N = alpha//lamda`
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