Starting with a sample of pure `.^66 Cu, 7//8` of it decays into `Zn` in `15 min`. The corresponding half-life is.

Options

A. 5 min
B. `7(1)/(2)min`
C. 10 min
D. 15 min

Answer

A

Explanation

According to the question, (7/8) part decays i.e., remaining part is (1/8).
We have, `N =N_(0)((1)/(2))^((t)/(T_(1//2)))implies1/8((1)/(2))^((15)/(T_(1//2)))`
`implies"Half-life"T_(1//2)=5min`