Assuming that about `200 MeV` of energy is released per fission of `._(92)U^(235)` nuceli, the mass of `U^(235)` consumed per day in a fission ractor of power `1` megawatt will be approximately .

Options

A. 10kg
B. 1kg
C. 1g
D. 10g

Answer

C

Explanation

As, `n=m/AN_(A)impliesE=m/AN_(A)xx200xx1.6xx10^(-13)J`
Power `=E/t=(mN_(A)xx3.2xx10^(-11))/(235xx24xx3600)=10^(6)`
Mass `=(1xx10^(6)xx24xx3600xx235)/(200xx1.6xx10^(-13)xx6.02xx10^(23))~~1g`