The half-life of radioactive Polonium `(Po)` is `138.6` days. For ten lakh Polonium atoms, the number of disintegrations in `24` hours is.

Options

A. 2000
B. 3000
C. 4000
D. 5000

Answer

D

Explanation

We, have, `n=(24)/(24xx138.6)=(1)/(138.6)`
Now, `(N)/(N_(0))=((1)/(2))^(n)=((1)/(2))^(1//138.6)`
`impliesN=1000000((1)/(2))^(1//1.38.6)=995011`
So, number of disintengration
`=1000000-995011=4989~~5000`