If radius of the `._(13)^(27)Al` nucleus is taken to be `R_(AI)`, then the radius of `._(53)^(125)Te` nucleus is nearly

Options

A. `((53)/(13))^(1//3)R_(Al)`
B. `5/3R_(Al)`
C. `3/5R_(Al)`
D. `((13)/(53))^(1//3)R_(Al)`

Answer

B

Explanation

(B) Radius of the nucleus is given by
` R=R_(0) A^(1//3)implies R prop A^(1//3)`
`therefore (R_(Al))/(R_(Te) ) =((A_(Al))/(A_(Te)))^(1//3) =((27)/(125))^(1//3)=(3)/(5)`
`R_(Te)=(5)/(3) R_(Al)`