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The half-life of a radioactive isotope X...

The half-life of a radioactive isotope `X` is `20 yr`. It decays to another element `Y` which is stable. The two elements `X` and `Y` were found to be in the ratio `1:7` in a sample of given rock. The age of the rock is estimated to be

A

40 yr

B

60 yr

C

80 yr

D

100 yr

Text Solution

Verified by Experts

The correct Answer is:
B

Ratio of X and Y =1 :7
`m_(x)/(m_(y))=(1)/(7)" "m_(y)=7m_(x)` Let the initial total mass =m
`implies m_(x)+m_(y)=m`
`implies(m_(y))/(7)+m_(y)=m`
`(8m_(y))/(7)=mimpliesm_(y)=(7)/(8)m`
Only `((1)/(8))th` part remains undisintegrated, number of half-lives involve are three as
`1overset(T_(1//2))to(1)/(2)overset(T_(1//2))to(1)/(4)overset(T_1//2)to(1)/(8)`
So, total time taken to become `(1)/(8)` unstable part
`=3T_(1//2)=3xx20yr=60yr`
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