A nucleus `._ZX^A` emits `9 alpha-`particles and `5p` particle. The ratio of total protons and neutrons in the final nucleus is.

Options

A. `((Z-13))/((A-36))`
B. `((Z-13))/((A-Z-13))`
C. `((Z-13))/((A-Z-23))`
D. `((Z-13))/((A-Z-23))`

Answer

D

Explanation

The given situation can be shown as
`""_(Z)X^(A)overset(9alpha)to""_(Z-18)X^(A-36)overset(5beta)to""_(Z-13)X^(A-36)`
Number of protons, P=(Z=13) and number of neutrons,
`N=(A-36)-(Z-13)=(A-Z-23)`
`(P)/(N)=((Z-13))/((A-Z-23))`