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t(1//2) is the half of a substance then ...

`t_(1//2)` is the half of a substance then `t_(3//4)` is the time in which substance

A

substance decays /12

B

substance decays (3/4) th

C

substance remains 1/2

D

substance remains (3/4) th

Text Solution

Verified by Experts

The correct Answer is:
B

`t_(1//2)` is given as the half-life of the substance i.e., substance decays half, so in `t_(3//4)` time in which substance decays `(3)/(4)th`.
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