The half-life of redioactive element is 600 yr. The fraction of sample that would remain after 3000 yr is

Options

A. `1//2`
B. `1//16`
C. `1//8`
D. `1//32`

Answer

D

Explanation

We know that, `n=(t)/(T)`
where, T=half-life
Given, t=3000yr
T=6000yr
`n=(3000)/(600)=5`
Then, `(N)/(N_(0))=((1)/(2))^(5)=(1)/(32)`