An air bubble of diameter `1 xx 10^(-3)m` rises in water. Calculate the terminal velocity of the bubble.

Explanation

Given `D=1 xx 10^(-3)m," "r=0.5 xx 10^(-3)m`
`h=1 xx 10^(-3)Nsm^(-2)," "r=1.293kgm^(-3)" "rho=10^(3)kgm^(-3)`
Using, `v_(1)=(2)/(0) (r^(2)g)/(eta) (rho-sigma) =2/9 ((0.5 xx 10^(-3))^(2)xx 9.8)/(10^(-3)) (1.293-1000)=-0.544ms^(-1)`
`-ve` sign indicates that the bubbles rises up in a given fluid.