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Calculate the critical velocity of water...

Calculate the critical velocity of water in a tube of diameter 0.25m. Given Reynold number =2500, density of water `=10^(3)kgm^(-3) and" viscosity"=10^(-3)Nsm^(-2)`.

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Given `R=2500", r=10^(3)kgm^(-3), h=10^(-3) Nsm^(-2)" "D=0.25m`
We know that `v_(c)=(Reta)/(rho D)=(2500 xx 10^(-3))/(10^(3) xx0.25) =0.01ms^(-1) v_(c)=1 cm s^(-1)`.
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