When a bouler of mass 240kg is placed on a floating iceberg, it is found that the iceberg just sinks. What is the mass of iceberg? (Given R.D. of ice=0.90 and density of sea water=1.02).

Explanation

Mass of bouler =240kg
Let the mass of iceberg =M
`rho_("ice")=90kgm^(-3)" "rhg_(w)=1020kgm^(-3)`
Applying (240+M)g= `vrho_(p_(w))g.` we get
`240+M=(M)/(rho)S_(w) 240=M((rho_(w))/(rho)-1)`
hence `M=(240)/((rho_(w))/(rho)-1) =(240)/((1020)/(900)-1)=(240 xx 45)/(rho)`
M=1800kg