Calculate pressure inside a small air bubble of radius `10^(-4)m` radius found just below the surface of water (given S.T. of water `=0.072 Nm^(-1) and" 1 atm "=1.013 xx 10^(5)Pa)`.

Explanation

Given, `r=10^(-4)m" "T=0.072Nm^(-1)" "P_(o)=1.013 xx 10^(5)Pa`
Excess of pressure inside an air bubble `P-P_(o)=(2T)/(R)`
i.e, `P=P_(o)+(2T)/(R)=(1.013 xx 10^(5))+(2 xx 0.072)/(10^(-4))=(1.013+0.0144)xx 10^(5)`
`P=1.0274 xx 10^(5) Nm^(-2) or Pa`.