Calculate the amount of work done is blowing a soap bubble to a radius of 0.05m by blowing the soap solution which has a surface tension of `0.03Nm^(-2)`.

Explanation

Given `T=0.30Nm^(-1)`
`r=0.05m`
We know that W=(T) (surface area)
Since soap bubble has two free surfaces
`SA=2(4pir^(2))=8pir^(2)`
Hence `W=T(8pir^(2))`
i.e, `W=0.3 xx 8 xx 3.142 xx (0.05)^(2)`
i.e, `W=1.88 xx 10^(-3)J`