Calculate the excess pressure inside a soap bubble of radius 1.0mm. (Given surface tension of soap solution `=0.040 Nm^(-1))`.

Explanation

Given `T=0.040 Nm^(-1)`
`r=1 xx 10^(-3)m`
We know that excess pressure inside soap bubble, `P=(4T)/(R)=(4 xx 0.04)/(1 xx 10^(-3))=160Nm^(-2)`