Calculate excess pressure inside an air bubble of radius 1.0 mm and just below the surface of water. What will be the pressure inside the soap bubble?

Explanation

Given `r=1 xx 10^(-3)m`
`T=0.072 Nm^(-1)`
Excess Pressure `=(2T)/(r)` (because it has only the inner suface= `(2 xx 0.072)/(1 xx 10^(-3))`
`=144 Nm^(-2) =0.00144 xx 10^(5)`
Net pressure inside the bubble is `=P_(0)+(2T)/(r)=1.013 xx 10^(5)+0.00144+10^(5)`
Net pressure `=1.0144 xx 10^(5)Nm^(-2)`