Water rises in a capilaary tube to a height of 2.0cm. In another capilary tube of radius one third of the first, water remains at a partricular height inside it. Find the height of water in the second capillary.

Explanation

Given `h_(1)=2cm" "r_(2)=(r_(1)/3)`
since `h alpha 1/r " "h_(2)/h_(1)=r_(1)/r_(2)`
i.e,` h_(2)=(r_(1)/r_(2))h_(1)=((3r_(2))/(r_(2))h_(1)=3 xx 2," "i.e, h_(2)=6cm.`