Sea water contains `1.15 xx 10^(4)` ppm of `Na^(+)` and `3.84 xx 10^(4)`ppm of `SO_(4)^(2-)`. Calculate sum of molar concentration of `Na^(+)` and `SO_(4)^(2-)`. [Given : density of Sea water is 1 gm/ml ]

Answer

9

Explanation

`Na^(+) rArr 1.15 xx 10^(4) gm Na^(+)` in `10^(6)` gm of solution
`SO_(4)^(2) rArr 3.84 xx 10^(4) gm SO_(4)^(2-)` in `10^(6)` gm of solution
`M_(Na^(+)) = (((1.15 xx 10^(4))/(23)))/(10^(6)) xx 1000 = 0.5`
`M_(SO_(4)^(2-)) = (((3.84 xx 10^(4))/(96)))/(10^(6)) xx 1000 = 0.4`
`M_("total") = M_(Na^(+)) + M_(SO_(4)^(2-))`
`= 0.5 + 0.4 = 0.9`
9