`Br_(2)` reacts with `O_(2)` in either of the following ways depending upon supply of `O_(2)`
`Br_(2) + (1)/(2) O_(2) rarr Br_(2) O`
`Br_(2) + (3)/(2) O_(2) rarr Br_(2) O_(3)`
If 4 moles of `Br_(2)` and 10 moles of `O_(2)` are taken in a container then calculate the number of moles of reactant left complete reaction.

Answer

4

Explanation

`{:(Br_(2),+,(3)/(2)O_(2),rarr,Br_(2)O_(3),),("Moles",4,,(3)/(2) xx 4,,),(,,,= 6 "moles",,):}`
Moles of reactant `(O_(2))` left = 4 moles