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A body starts from rest and is uniformly...

A body starts from rest and is uniformly accelerated for `30` s. The distance travelled in the first `10` s is `x_(1)`, next `10` s is `x_(2)` and the last `10` s is `x_(3)`. Then `x_(1):x_(2):x_(3)` is the same as :-

A

`1:2:3`

B

`1:2:5`

C

`1:3:5`

D

`1:3:9`

Text Solution

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The correct Answer is:
C
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