When iodine is passed through aqueous solutions of NaF, NaBr and NaCl

Options

A. It gives mixture of `F_2 , Cl_2 and Br_2`
B. It gives chlorine
C. It gives bromine
D. None of these

Answer

To solve the question of what happens when iodine is passed through aqueous solutions of NaF, NaBr, and NaCl, we can follow these steps:

### Step 1: Understanding the Reactants
- We have three sodium halides: NaF (sodium fluoride), NaBr (sodium bromide), and NaCl (sodium chloride).
- Iodine (I2) is a diatomic molecule and is a halogen.

### Step 2: Analyzing the Reactivity
- Among the halogens, the order of reactivity is as follows: Fluorine (F) > Chlorine (Cl) > Bromine (Br) > Iodine (I).
- Iodine is the least reactive halogen due to its lower electronegativity compared to fluorine, chlorine, and bromine.

### Step 3: Predicting the Reaction
- When iodine is introduced to the aqueous solutions of NaF, NaBr, and NaCl, we need to consider whether iodine can displace any of the halides present.
- Since iodine is less reactive, it cannot displace fluorine, bromine, or chlorine from their respective sodium salts.

### Step 4: Conclusion
- Therefore, when iodine is passed through the aqueous solutions of NaF, NaBr, and NaCl, no chemical reaction occurs.
- As a result, no new products are formed, and we conclude that the answer is that there is no reaction.

### Final Answer
- The correct option is that there is no reaction when iodine is passed through these solutions, which corresponds to option number 4: "none of these."