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Calculate the cell constant if the speci...

Calculate the cell constant if the specific conductance of a Solution is 0.2 `"ohm"^(-1)cm^(-1)` and its conductance is 0.04 `"ohm"^(-1)`.

A

`1 cm^(-1)`

B

`0 cm^(-1)`

C

`5 cm^(-1)`

D

`0.2 cm^(-1)`

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The correct Answer is:
To calculate the cell constant, we can use the relationship between specific conductance (κ), conductance (G), and the cell constant (G*). The formula we will use is: \[ G^* = \frac{κ}{G} \] Where: - \( G^* \) is the cell constant (in cm\(^{-1}\)) - \( κ \) is the specific conductance (in ohm\(^{-1}\)cm\(^{-1}\)) - \( G \) is the conductance (in ohm\(^{-1}\)) ### Step-by-Step Solution: 1. **Identify Given Values**: - Specific conductance (κ) = 0.2 ohm\(^{-1}\)cm\(^{-1}\) - Conductance (G) = 0.04 ohm\(^{-1}\) 2. **Substitute the Values into the Formula**: \[ G^* = \frac{κ}{G} = \frac{0.2 \, \text{ohm}^{-1}\text{cm}^{-1}}{0.04 \, \text{ohm}^{-1}} \] 3. **Perform the Division**: - The units of ohm\(^{-1}\) will cancel out: \[ G^* = \frac{0.2}{0.04} \, \text{cm}^{-1} \] 4. **Calculate the Result**: \[ G^* = 5 \, \text{cm}^{-1} \] ### Final Answer: The cell constant \( G^* \) is 5 cm\(^{-1}\). ---
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