A body starts from rest and acquires velocity `V` in time `T`. The instantaneous power delivered to the body in time 't' proportional to

Options

A. `(v//T)t`
B. `(v^(2)//T)t^(2)`
C. `(v^(2)//T^(2))t`
D. `(v^(2)//T^(2))t^( 2)`

Answer

D

Explanation

`KE=(1//2)mv^(2)=m/2(at)^(2)`
`=m/2 (v/T t)^(2) :. a=(Deltav)/(Delta t)=v/T`
`K.E. prop (v^(2))/(T^(2))t^(2)`
Hence (D) is correct.