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The ratio of the earth's orbital angular...

The ratio of the earth's orbital angular momentum (about the Sun) to its mass is `4.4 xx 10^(15) m^(2) s^(-1)`. The area enclosed by the earth's orbit is approximately-___________m^(2).

A

`7xx10^(22)m^(2)`

B

`6.02xx10^(23)m^(2)`

C

`7xx10^(23)m^(2)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`(L)/(M_(e ))=4.4xx10^(15)`
`implies(M_(e )vr)/(M_(e ))=4.4xx10^(15)` …………`(1)`
`(GMm)/(r^(2))=(mv^(2))/(r )impliesGM=v^(2)r`
`implies((2pir)/(365xx24xx60xx60))r=4.4xx10^(15)`
`impliespir^(2)~~7xx10^(22)m^(2)`
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