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What is the fractional decrease in the v...

What is the fractional decrease in the value of free-fall acceleration g for a particle when it is lifted from the surface to an elevation `h`? `(h lt lt R)`

A

`h//R`

B

`-2h//R`

C

`2h//R`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`g=(GM)/(R^(2))`……..`(i)`
`(dg)/(dR)=(-2GM)/(R^(3))`
Putting `dR=h` we obtain
`implies(dg)/(h)=(-2GM)/(R^(2)).(1)/(R )`……….`(ii)`
From `(i)` and `(ii)`
`implies(dg)/(g)=-2((h)/(R ))`
Change is `-ve`
That means `g` decreases.
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