Home
Class 12
PHYSICS
Transverse wave is described by the equa...

Transverse wave is described by the equation `y=y_0 sin 2pi (ft-x/lambda)` .The maximum particle velocity is twice the wave velocity if wavelength is____

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the given equation of the transverse wave and apply the relationships between particle velocity, wave velocity, and wavelength. ### Step-by-Step Solution: 1. **Understand the Wave Equation**: The transverse wave is described by the equation: \[ y = y_0 \sin\left(2\pi\left(ft - \frac{x}{\lambda}\right)\right) ...
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY AND WAVES

    FIITJEE|Exercise Assignment Problems (Subjective) Level-II & III|15 Videos
  • ELASTICITY AND WAVES

    FIITJEE|Exercise Assignment Problems (Objective) Level-I|40 Videos
  • ELASTICITY AND WAVES

    FIITJEE|Exercise Assignment Problems (Subjective) Level-I (Short Answer)|8 Videos
  • CURRENT ELECTRICITY

    FIITJEE|Exercise Comprehension -4|3 Videos
  • ELECTROMAGNETIC INDUCTION

    FIITJEE|Exercise EXERCISE|9 Videos

Similar Questions

Explore conceptually related problems

A transverse wave is described by the equation y=A sin [2pi(ft-x//lambda)] . The maximum particle velocity is equal the wave velocity if :

A transverse wave is described by the equation y=A sin 2pi( nt- x//lambda_0) . The maximum particle velocity is equal to 3 times the wave velocity if

A transverse wave is described by the equation y= A sin 2 pi (vt - x/lambda) . The maximum particle velocity is equal to four times the wave velocity if

A transverse wave is derscried by the equation y=y_(0) sin 2 pi (ft - (x)/(lamda)) . The maximum particle velocity is equal to four times the wave velocity if :-

A transverse wave is described by the equation y=y_(0)sin4pi(upsilont-(x)/(lambda)) . The maximum particle velocity is equal to four times the wave velocity if

A travelling wave is described by the equation y = y_(0) sin ((ft - (x)/lambda)) . The maximum particle velocity is equal to four times the wave velocity if

A transverse wave is given by y=A sin 2 pi ((t)/(T)-(x)/(lambda)) . The maximum particle velocity is equal to 4 times the wave velocity when

A simple harmonic wave is represent by the relation y(x,t)=a_(0) sin 2pi(vt-(x)/(lambda)) if the maximum particle velocity is three times the wave velocity, the wavelength lambda of the wave is