Show that `|(2z + 5)(sqrt2-i)|=sqrt(3) |2z+5|`, where z is a complex number.

show that |2bar(z)+5|(sqrt(2)-1)|=sqrt(3)|2z+5| where z is a complex number.

If |z-2|=min{|z-1|,|z-5|}, where z is a complex number then

Number of solutions of Re(z^(2))=0 and |Z|=a sqrt(2) , where z is a complex number and a gt 0 , is

If z^2 = 12 sqrt(-1) , find the complex number z .

If arg ((z-(10+6t))/(z-(4+2i)))=(pi)/(5) (where z is a complex number), then the perimeter of the locus of z is

If |Z-i|=sqrt(2) then arg((Z-1)/(Z+1)) is (where i=sqrt(-1)) ; Z is a complex number )

The point z_(1)=3+sqrt(3)i and z_(2)=2sqrt(3)+6i are given on la complex plane.The complex number lying on the bisector of the angel formed by the vectors z_(1)andz_(2) is z=((3+2sqrt(3)))/(2)+(sqrt(3)+2)/(2)iz=5+5iz=-1-i none of these

The least value of |z| where z is complex number which satisfies the inequality exp (((|z|+3)(|z|-1))/(|z|+1|)log_(e)2)gtlog_(sqrt2)|5sqrt7+9i|,i=sqrt(-1) is equal to :

If z=x+iy=((1)/(sqrt2)-(i)/(sqrt2))^(-25), where i=sqrt(-1), then what is the fundamental amplitude of (z-sqrt2)/(z-sqrt2) ?