Calculate the angular frequency of an electron occuppying the second Bohr orbit of `He^(+)` ion.

Explanation

Velocity of an electron in `He^(+)` ion in an orbit `=(2piZe^(2))/(nh)`………..i
Radius of `He^(+)` ion in an orbit `=(n^(2)h^(2))/(4pi^(2)me^(2)Z)` ………….ii
By eqs (i) and (ii), angular velocity `(omega)=u/r=(8pi^(3)Z^(2)Me^(4))/(n^(3)h^(3))`……..iii
`=(8xx(22//7)^(3)xx(2)^(2)xx(9.108xx10^(-28))xx(4.803xx10^(-10))^(4))/((2)^(3)xx(6.626xx10^(-27))^(3))`
`=2.067xx10^(16)"sec"^(-1)`