The `lambda` of `H_(alpha)` line of the Balmer series is `6500 Å`. What is the `lambda` of `H_(beta)` line of the Balmer series?

Explanation

For `H alpha` line of Balmer series `n_(1)=2, n_(2)=3`
For `H_(beta)` line of Balmer series `n_(1)=2,n_(2)=4`
`:.1/(lamda_(alpha))=R_(H)[1/(2^(2))-1/(3^(2))]`…………I
and `1/(lamda_(beta))=R_(H)[1/(2^(2))-1/(4^(2))]`………..ii
By Eqs I and ii
`lamda_(beta)=lamda_(alpha)=(80//108)=6500xx(80//108)`
`=481.8Å`