Home
Class 12
CHEMISTRY
Show that the circumference of the Bohr ...

Show that the circumference of the Bohr orbit for the hydrogen atom is an integral multiple of the de Broglie wavelength associated with the electron revolving around the orbit.

Text Solution

Verified by Experts

According to de Broglie.
`lamda=h/("mu")`……….i
Also mur `=(nh)/(2pi)`…….ii
By eqs (i) and (ii) `lamda=(h.2pir)/(n.h)`
or `2pir=n lamda`
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    FIITJEE|Exercise SOLVED PROBLEMS (SUBJECTIVE)|16 Videos

  • ATOMIC STRUCTURE

    FIITJEE|Exercise SOLVED PROBLEMS (OBJECTIVE)|28 Videos

  • ALKYL AND ARYL HALIDES

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS|1 Videos

  • CARBOHYDRATES, AMINO ACIDS, POLYMERS AND PRACTICAL ORGANIC CHEMISTRY

    FIITJEE|Exercise EXERCISE|4 Videos

Similar Questions

Explore conceptually related problems

What is the de-Broglie wavelength associated with the hydrogen electron in its third orbit

The De Broglie wavelenght associated with electron in n Bohr orbit is

The de-Broglie wavelength of an electron revolving in the ground state orbit is

State the expression for the radius of the nth Bohr orbit in a hydrogen atom. Hence state the expression for the de Broglie wavelength associated with the electron in this orbit.

Determine the de-Broglie wavelength associated with an electron in the 3rd Bohr's orbit of He^+ ion.

The circumference of circular orbit of electron in a He^(+) ion is five times the de-Broglie wavelength associated with the electron. Find the radius of the orbit.

The radius of the second orbit of an electron in hydrogen atom is 2.116A . The de Broglie wavelength associated with this electron in this orbit would be

The circumference of the second orbit of an atom or ion having single electron is 4 nm the de Broglie wavelength of electron (in nm) revolving in this orbit si :