Why electron cannot exist inside the nucleus according to Heisenberg's uncertainty principle?

Explanation

Diameter of the atomic nucleus is of the order of `10^(-15)m`
The maximum uncertainty in the position of electron is `10^(-15)`m.
Mass of electron `=9.1xx10^(-31)kg`
`Deltax.Deltap=h/(4pi)`
`Deltax xx (m.Deltav)=h//4pi`
`Deltav=h/(4pi)x1/(Deltax.m)=(6.63xx10^(-34))/(4xx22/7)xx1/(10^(-15)xx9.1xx10^(-31))`
`Deltav=5.80xx10^(10)ms^(-1)`
This value is much higher than the velocity of light and hence not possible.