Home
Class 12
CHEMISTRY
The Wave function (Psi) of 2s is given b...

The Wave function `(Psi)` of 2s is given by:
`Psi_(2s)=(1)/(2sqrt2pi)(1/a_(0))^(1//2){2-(r)/a^(0)}e^(-r//2a_(0))`
At `r =r_(0)`, radial node is formed . Thus for 2s `,r_(0),` in terms of `a_(0)` is-

A

`r_(0)=a_(0)`

B

`r_(0)=2a_(0)`

C

`r_(0)=a_(0)//2`

D

`r_(0)=4a_(0)`

Text Solution

Verified by Experts

The correct Answer is:
B
`psi_(2s)=1/(2sqrt(2pi))[1/(a_(0))]^(1//2)[2-r/(a_(0))]e^(-r//2a_(0))`
For radia node at `r=r_(0),phi_(2s)^(2)=0`. This is possible only when `[2-(r_(0))/(a_(0))]=0`
`:.r_(0)=2a_(0)`
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    FIITJEE|Exercise SOLVED PROBLEMS (SUBJECTIVE)|16 Videos

  • ATOMIC STRUCTURE

    FIITJEE|Exercise SOLVED PROBLEMS (OBJECTIVE)|28 Videos

  • ALKYL AND ARYL HALIDES

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS|1 Videos

  • CARBOHYDRATES, AMINO ACIDS, POLYMERS AND PRACTICAL ORGANIC CHEMISTRY

    FIITJEE|Exercise EXERCISE|4 Videos

Similar Questions

Explore conceptually related problems

Consider psi (wave function) of 2s atomic orbital of H-atom is- psi_(2s)=(1)/(4sqrt(2pia_(0)^(3//2)))[2-(r )/(a_(0))]e^.(r )/(2a_(0) Find distance of radial node from nucleous in terms of a_(0)

The wave function of 2s electron is given by W_(2s) = (1)/(4sqrt(2pi))((1)/(a_(0)))^(3//2)(2 - (r )/(a_(0)))e^(-1 a0) It has a node at r = r_(p) .Find the radiation between r_(p) and a

The wave function of 3s electron is given by Psi_(3s)=1/(81sqrt(3)prod)(1/a_(0))^(3//2)[27-18(r/a_(0))+2(r/a_(0))^(2)]e^(-r//3a_(0)) It has a node at r=r_(0) , Find out the relation between r_(0) and a_(0)

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :

a.The schrodinger wave equation for hydrogen atom is psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^((3)/(2)) (2 - (r_(0))/(a_(0)))e^((-(r )/(a)) When a_(0) is Bohr's radius Let the radial node in 2s be n at Then find r_(0) in terms of a_(0) b. A base ball having mass 100 g moves with velocity 100 m s^(-1) .Find the value of teh wavelength of teh base ball

The wave function for 2s orbital is given as: Psi = ((1)/(sqrt2)) ((1)/(alpha_(0)))^(3//2)(2- (r)/(alpha_(0))).e^(-r//2alpha_(0) Where alpha_(0) = First Bohr's radius in H-atom =0.529 "Å" Read the given statement and pick out the correct statement(s).

The Schrodinger wave equation for hydrogen atom is psi_(2s) =1/(4sqrt(2pi)) (1/(a_(0)))^(3//2)(2-r/(a_(0)))e^(-t//a_(0)) where a_0 is Bohr's radius. If the radial node in 2 s be at r_0 , then r_0 would be equal to