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The angular velocity of an electron occu...

The angular velocity of an electron occupying the second Bohr orbit of `He^(+)` ion is `("in" sec^(-))`:

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Velocity of an electron in `He^(+)` ion in a orbit `(u)=(2piZe^(2))/(nh)` ……1
Radius of `He^(+)` ion in an orbit `(r_(n))=(n^(2)h^(2))/(4pi^(2)me^(2)Z)`………..2
By equation 1 and 2
Angular velocity `(omega)=u/r=(8pi^(3)Z^(2)me^(4))/(n^(3)h^(3))`
`=(8xx(22/7)^(3)xx2^(2)xx(9.108xx10^(-28))xx(4.803xx10^(-10))^(4))/(2^(3)xx(6.626xx10^(-27))^(3))`
`=2.067xx10^(16)"sec"^(-1)`
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