Home
Class 12
CHEMISTRY
The Lyman series of the hydrogen spectru...

The Lyman series of the hydrogen spectrum can be represented by the equation `nu = 3.2881 xx 10^(15)s^(-1)[(1)/((1)^(2)) - (1)/((n)^(2))] ` (where n = 2,3,…….)
Calculate the maximum and minimum wavelength of the lines in this series.

Text Solution

Verified by Experts

`barv=1/(lamda)=1/v=(3.2881xx10^(15))/(3xx10^(8))m^(-1)[1/((1)^(2)-1/(n^(2)))]`
Wavelength is maximum `(barv_("min"))` when n is minimum so that `1/(n^(2))` is maximum.
`:.barv=1/(lamda_("max"))=(3.2881xx10^(15))/(3xx10^(8))[1/((1)^(2) )-1/((2)^(2))]`
`:.lamda_("max")=(3xx10^(8))/(3.2881xx10^(15))xx4/3`
`=1.2165xx10^(-7)m=121.67` min
Wavelength is minimum `(barv_("max"))` when n is `oo`
i.e. series converge
`v_("max")=1/(lamda_("min"))=(3.2881xx10^(15))/(3xx10^(8))`
`:.lamda_("min")=0.9124xx10^(-7)m 91.24nm`
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    FIITJEE|Exercise SOLVED PROBLEMS (OBJECTIVE)|28 Videos

  • ATOMIC STRUCTURE

    FIITJEE|Exercise COMPREHENSION-I|3 Videos

  • ATOMIC STRUCTURE

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS INDICATED BY DIGITAL INTEGER BY XXXXX.XX|2 Videos

  • ALKYL AND ARYL HALIDES

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS|1 Videos

  • CARBOHYDRATES, AMINO ACIDS, POLYMERS AND PRACTICAL ORGANIC CHEMISTRY

    FIITJEE|Exercise EXERCISE|4 Videos

Similar Questions

Explore conceptually related problems

The Lyman series of the hydrogen spectrum can be represensted by the equation v = 3.2881 xx 10^(15)s^(-1)[(1)/((1)^(2)) - (1)/((n)^(2))] [where n = 2,3,…….) Calculate the maximum and minimum wavelength of the lines in this series

The Lyman series of hydrogen spectrum lies in the region :

The Lyman series of hydrogen spectrom can be respectively by the equation v = 3.28 xx 10^(15)[(1)/(1^(2)) - (1)/(n^(2))] s^(-1) Calculate the maximum and minimum frequencies in this series

Calculate the shortest and longest wavelength in hydrogen spectrum of Lyman series.

Emission transitions in the Paschen series end at orbit n = 3 and start from orbit n and can be represented as v = 3.29 xx 10^(15) (Hz) [1//3^2 - 1//n^2] . Calculate the value of n if the transition is observed at 1285 nm. Find the region of the spectrum.