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The angular momentum of electron in a ...

The angular momentum of electron in a Bohr's orbit of H atom is `4.2178 xx 10^(-34) kg m^(2)s^(-1)`. Calculate the wavelength of the spectral line when the electrton falls from this level to the next lower level.

Text Solution

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`mvr=(nh)/(2pi)`
`(nh)/(2pi)=4.2178xx10^(-34)`
`n=(4.2478xx10^(-34)xx2xx3.14)/(6.625xx10^(-34))=4`
`1/(lamda)=R[1/(n_(1)^(2)-1/(n_(2)^(2)))]`
The wavelength for transition from n=4 to n=3
`1/(lamda)=109678p[1/(3^(2))-1/(4^(2))]`
`lamda=1.8xx10^(-4)cm`
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