For a d-electron, the orbital angular momentum is

Options

A. `sqrt(6)h`
B. `sqrt(2)h`
C. `h`
D. `2h`

Explanation

To find the orbital angular momentum for a d-electron, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Quantum Number (l)**:
- For d-orbitals, the azimuthal quantum number \( l \) is equal to 2.

2. **Use the Formula for Orbital Angular Momentum**:
- The formula for calculating the orbital angular momentum \( L \) is given by:
\[ L = \sqrt{l(l + 1)} \cdot h \]
- Here, \( h \) is Planck's constant.

3. **Substitute the Value of l**:
- Substitute \( l = 2 \) into the formula:
\[ L = \sqrt{2(2 + 1)} \cdot h \]

4. **Calculate the Expression Inside the Square Root**:
- Calculate \( 2 + 1 = 3 \).
- Now, substitute this back into the equation:
\[ L = \sqrt{2 \cdot 3} \cdot h \]

5. **Simplify the Expression**:
- Calculate \( 2 \cdot 3 = 6 \):
\[ L = \sqrt{6} \cdot h \]

6. **Final Result**:
- Therefore, the orbital angular momentum for a d-electron is:
\[ L = \sqrt{6} \cdot h \]

### Final Answer:
The orbital angular momentum for a d-electron is \( \sqrt{6} \cdot h \).

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