If the nitrogen atom has electronic configuration `1s^(7)`, it would have energy lower than that of the normal ground state configuration `1s^(2)2s^(2)2p^(3)` because the electrons would be closer to the nucleus. Yet `1s^(7)` is not observed because it violates

Options

A. Heisenberg's uncertainty principle
B. Hund's rule
C. Pauli exclusion principle
D. Bohr's postulate of stationary orbits

Answer

C

Explanation

According to Paull.s exclusion principle an orbtial cannot have more than two electrons and these two with opposite spin.
Hence c, is the correct answer.