The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV`. The possible energy values (s) of the excited state (s) for electron in bohr orbits of hydrogen is (are)

Options

A. `-3.4eV`
B. `-4.2eV`
C. `6.8eV`
D. `+6.8eV`

Answer

A

Explanation

`E_(n)=(-13.6)/(n^(2))eV`
When `n=2, E_(2)=(-13.6)/4=-3.4eV`
Hence A is the correct answer.