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Let of waveldnth lamda shines on a metal...

Let of waveldnth `lamda` shines on a metal surface with intensity x and the metal emits Y electrons per second of average energy, Z. What will happen to Y and Z if x is doubled?

A

Y will be doubled and Z will become half

B

Y will remain same and Z will be doubled

C

Both Y and Z will be doubled.

D

Y will be doubled but Z will remain same

Text Solution

Verified by Experts

The correct Answer is:
D
When intensity is doubled number of electrons emitted per second is also doubled but average energy of photoelectrons emitted remains the same.
Hence D is the correct answer.
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FIITJEE-ATOMIC STRUCTURE-SOLVED PROBLEMS (OBJECTIVE)
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  4. What transition in the hydrogen spectrum would have the same wavelen...

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  5. The energy of second Bohr orbit of the hydrogen atom is - 328 k J mol^...

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  6. Principal azimuthal , and magnetic quantum numbers are respetively r...

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  8. Difference between n^(th) and (n+1)^(th) Bohr's radius of H atom is eq...

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  9. The dissociation energy of H(2) is 430.53 kJ mol^(-1), If H(2) is of d...

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  10. Number of waves in third Bohr's orbit of hydrogen will be

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  11. In hydrogen atom are excited in the fifth level .The number of line ...

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  12. If a(0) represents the bOhr radius, the de Broglie wavelength of the e...

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  13. Let of waveldnth lamda shines on a metal surface with intensity x and ...

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  14. Ground state electronic configuration of nitrogen atom can be represen...

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  17. Which of the following statement (s) is (are) correct?

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  19. Which of the following statements are correct?

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  20. The magnitude of spin angular momentum of an electron is given by

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