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The velocity of electron in a certain Bo...

The velocity of electron in a certain Bohr orbit of H bears the ratio `1: 275 ` to the velocity of light M
a. What is the quantum number (n) of orbit ?
b. Calculate the wave number of the radiation emitted whemn the electron jumps from `(n + 1)` state to the ground state `(R = 1.0987 xx 10^(5) cm^(-1))`

Text Solution

Verified by Experts

Velocity of electron in certain Bohr.s orbit `(U_(x))=1/275xx` velocity of light.
`=1/275xx3xx10^(10)=1.09xx10^(8)cmS^(-1)`
Also `U_(x)=(2pie^(2))/(nh)`
`implies1.09xx10^(8)=(2xx3.14xx(4.803xx10^(-10))^(2))/(6.626xx10^(-27)xxn)`
`:.n=2.006~~2`
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