What is the pH of `10^(-2)NH_(2)SO_(4)`?

Explanation

To find the pH of a `10^(-2) N H2SO4` solution, we can follow these steps:

### Step 1: Understand the Normality of H2SO4
H2SO4 (sulfuric acid) is a strong acid that dissociates completely in solution. Each molecule of H2SO4 can release two protons (H+ ions). Therefore, the normality (N) of the solution indicates the number of equivalents of H+ ions per liter.

### Step 2: Calculate the Concentration of H+ Ions
Given that the normality of the solution is `10^(-2) N`, and since H2SO4 can release 2 H+ ions, the concentration of H+ ions will be:
\[ \text{Concentration of H}^+ = 2 \times \text{Normality} = 2 \times 10^{-2} \, \text{N} = 2 \times 10^{-2} \, \text{mol/L} \]
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