Conjugate acid of `[Zn(OH)(H_(2)O)_(5)]^(2+)`  is

Options

A. `[Zn(H_(2)O)_(5)]^(2+)`
B. `[Zn(H_(2)O)_(6)]^(+3)`
C. `[Zn(OH)(H_(2)O)_(6)]^(+3)`
D. `[Zn(OH)(H_(2)O)_(6)]^(+2)`

Answer

To find the conjugate acid of the complex ion \([Zn(OH)(H_2O)_5]^{2+}\), we need to follow these steps:

### Step 1: Identify the Base
The given complex ion \([Zn(OH)(H_2O)_5]^{2+}\) can act as a base. In this case, the hydroxide ion (OH⁻) is the part that can accept a proton (H⁺).

### Step 2: Protonation of the Base
When the base accepts a proton (H⁺), it will convert the hydroxide ion (OH⁻) into water (H₂O). Therefore, we add one proton (H⁺) to the hydroxide ion.

### Step 3: Write the New Complex
By adding a proton to the hydroxide ion in the complex, we will have:
\[ [Zn(OH)(H_2O)_5]^{2+} + H^+ \rightarrow [Zn(H_2O)_6]^{3+} \]

### Step 4: Determine the Charge
The original complex has a charge of +2. When we add one proton (H⁺), the overall charge of the new complex becomes +3.

### Step 5: Final Conjugate Acid
Thus, the conjugate acid of \([Zn(OH)(H_2O)_5]^{2+}\) is \([Zn(H_2O)_6]^{3+}\).

### Answer
The conjugate acid of \([Zn(OH)(H_2O)_5]^{2+}\) is \([Zn(H_2O)_6]^{3+}\).

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