A particle executes simple harmonic motion with an amplitude of 10 cm and time period 6s. Ast t=0 it is at position x=5 cm going towasrds positive x-direction. Write the eqwuation for the displacement x at time t. Find the magnitude of the acceleration of the particle at t=4s.

Answer

`x = (10 cm) sin [((pi)/(3)s^(-1))t + (pi)/(6)]`
`(10)/(9)pi^(2) prop 11 cm//s^(2)`